We will define our skier as they are above. Now, we will set V0x=20m/s,
V0y=3m/s. V¬0 is defined by the initial velocity, which in this case is
the speed in which our skier leaves a jump whose peak is set 5m above parallel.
The question now is, how far away from the jump will you land? The following
graph is a rough illustration of the jump at hand, which takes off from a
sloped hill and continues down that sloped hill.
We then use the following properties of physics to understand further and
solve for needed variables. We will first solve for both our x and y components,
which are as follows (Van Biezen, Physics - Mechanics: Motion In Two-Dimensions: (13 of 21) Example 2: Landing on a Slope 2013), (City, Ski Jumping - Intro to Physics 2015).
We also note that x=y, which leads to the following derivation of t
d in this case is the total distance traveled, which we is about 5.46 m, relative
to the ground. y in this case is equal to -.006 m, which actually means that you
as the gutsy ski jumper descended a total of 5.006 m from your moment of takeoff,
along with traveling 5.46 m linearly.
Now that you have made it through all of this, the next arrow at the bottom will simply lead you back to the home
page. Please enjoy the project video in the top right corner and have a good one!
